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Ethylene glycol (IUPAC name: ethane-1,2-diol) is an organic compound widely used as an automotive antifreeze and a precursor to polymers. In its pure form, it is an odorless, colorless, syrupy, sweet-tasting liquid. Ethylene glycol is toxic, and ingestion can result in death. Ethylene glycol is not to be confused with diethylene glycol, a heavier ether diol, or with polyethylene glycol, a nontoxic polyether polymer. ProductionFrom Wikipedia under the
GNU Free Documentation License  obspm.fr 496px x 677px | 10.10kB [source page] e this molecule has two alcohol functions It is commonly used as antifreeze in coolant fluids for car engines It was recently identified in interstellar clouds in the Galactic Centre One of the spectra observed at IRAM showing three lines of ethylene glycol and lines of other organic molecules Ethylene glycol was identified from about ten lines in spectra of comet  tennoji-h.oku.ed.jp 714px x 1194px | 44.70kB [source page] ethylmethylether s gif 27 Jan 2004 00 00 125k ethylmethylether b gif 27 Jan 2004 00 00 65k ethylene s gif 27 Jan 2004 00 00 81k ethylene b gif 27 Jan 2004 00 00 45k ethylene glycol s gif 27 Jan 2004 00 00 120k ethylene glycol b jpg 27 Jan 2004 00 00 16k ethylene glycol b gif 27 Jan  mocho.pt 600px x 800px | 18.30kB [source page] Ethane 1 2 diol ethylene glycol jpg 18 3kb From Yahoo Image Search: "Ethylene glycol"  blog.tutorvista.com Srinivas Mon, 12 Apr 2010 07:52:57 GM Calculate the amount of . ethylene glycol. (C2H6O2) dissolved in 3.55Kg of water if it depresses the freezing point of water by 22oC. (Kf of water=1.86C/m).  pagerankstudio.com admin Mon, 21 Jun 2010 07:08:05 GM The first symptom of . ethylene glycol. ingestion is similar to the feeling caused by the consumption of alcohol. Within a few hours, more toxic effects. Symptoms may include nausea, vomiting, seizures, stupor and even coma. ...  babonline.org G Wu, X Fan, H Wu, N Liu, J Ding, L Gou, R Zhao, T Xi Fri, 21 May 2010 15:31:03 GM HUVEC, human umbilical-vein endothelial cells; IPTG, isopropyl -D-thiogalactoside; LB, Luria Bertani; NGF, nerve growth factor; PEG8000, poly(. ethylene glycol. ) 8000; pfu, plaque-forming units; scFv, single-chain variable fragment; ... From Google Blog Search: "Ethylene glycol"  news.google.com The Engineer The olefins and aromatics feedstock will be used for downstream chemical plants located on Jurong Island, including the Shell mono- ethylene glycol (MEG) ... Shell announces start-up of new ethylene cracker Fibre2fashion.com all 4 news articles » news.google.com Derby Evening Telegraph PDSA senior veterinary surgeon Elaine Pendlebury said: "Dogs and cats are often attracted to the sweet taste of a chemical called ethylene glycol used in ... From Google News Search: "Ethylene glycol" You want to prepare an aqueous solution of ethylene glycol HOCH2CH2OH, in which the mole fraction of solute? Q. is 0.125. What mass of ethylene glycol, in grams should you combine with 955g ofwater? What is the molarity of the solution? Asked by Betsy R - Tue Oct 21 01:19:43 2008 - - 1 Answers - 0 Comments A. Moles water = 955 g / 18 g/mol = 53.1 mole fraction solute = moles solute / moles water + moles solute let x = moles solute 0.125 = x / 53.1+x 6.64 + 0.125 x = x x = 7.59 moles HOCH2CH2OH mass HOCH2CH2OH = 7.59 mol x 62 g/mol = 470.5 g To know the molarity I must know the density of the solution Answered by Dr.A - Tue Oct 21 04:17:12 2008 Find the molality, molarity and mole fraction of ethylene glycol? Q. An aqueous antifreeze solution is 40% ethylene glycol(C2H6O2) by mass. The density of the solution is 1.05g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol. Asked by westafrica88 - Wed Mar 7 14:08:18 2007 - - 1 Answers - 0 Comments A. Take 1 liter of solution. Since its density is given us 1.05 g/cm3 we know that 1 L must weight (1000 mL)(1.05)= 1050 g Of this total weight 40% is C2H6O2. (0.40)(1050)= 420 g C2H6O2 One mole weights 62 g 420/62=6.77 moles M=6.77/1 =6.77 M Molality= Mole C2H6O2/ Kg H2O In 1 Kg there are 400 g C2H6O2 and 600 g H2O(=0.600 Kg) 400/62=6.45 mole m=6.45/0.600=10.75 m In 1 Kg there are 400 g C2H6O2>>6.45 moles and 600 g H2O (MM=18) >>33.3 moles Total moles=6.45+33.3 = 39.8 X(C2H6O2) = 6.45/39.8=0.163 X(H2O) = 33.3/39.8=0.837 Answered by Non piu attiva su answers - Wed Mar 7 15:12:46 2007 How do you predict the solubility of ethylene glycol in water? Explain briefly thanks:D?
Q. How do you predict the above when your teacher only taught you alkanes, alkenes, alcohols, acids so far? Oh and the different reactions giving rise to different products, such as alcohols + acids --> esters + water? Please help. Thanks:D Asked by juzme - Sat Aug 22 10:29:35 2009 - - 1 Answers - 0 Comments A. Ethylene glycol is a 'diol' that means it is an alcohol with two alcohol groups. Compare the properties of alcohol to an alkane; then following the trend, predict ethylene glycol. The properties are arise from the interactions originating from the hydroxy group - hydrogen bonding. The Hydroxy group makes the alkane soluble in water, raises the boiling point and makes the compound more viscous. The presence of two hydroxy groups as in glycol will therefore make the BP even higher, the compound will be thicker/more viscous and highly soluble. There are so many reactions that it would not be possible to list them, however here are a two that may be of interest: Acid + Acid -> Acid anhydride + water Alcohol + Alcohol -> Ether + water Answered by Filpi - Tue Aug 25 08:56:59 2009 From Yahoo Answer Search: "Ethylene glycol" |
